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NEW QUESTION: 1
Shannon is preparing to apply an upgrade to IBM Connections. Before she does, she is backing up the Connections install. She stopped all the Connections servers and used native tools to backup the databases. She also backed up the Deployment Manager and Application Server profile directory, the Connections installation directory, profileRegistry.xml and the local and shared data directories. What are the other two items she should back up to ensure that she can fully recover if she has serious problems with the upgrade?
A. shared resource directory
B. IBM Installation Manager
C. IBM Tivoli Directory Integrator
D. customized configuration files
E. tdisol
Answer: A,D

NEW QUESTION: 2
The city table has the following structure:

Consider the statement with an incorrect field name:
PREPARE countryBYID FROM 'SELECT country FROM city WHERE ID=?,
What happens if a prepared statement named countryByID already exists when the above statement is executed?
A. An unknown column error will result and the old prepared statement definition will remain in effect.
B. A duplicate name error will result because a prepared statement with the same name already exists.
C. An unknown column error will result and no prepared statement named countryByID will exist.
D. A warningwill result and the old prepared statement definition will remain in effect.
Answer: B

NEW QUESTION: 3
What commonly causes a client-to-AP link imbalance?
A. The AP's transmit power is significantly lower than the client's transmit power
B. The client's antenna gain is lower than the AP's antenna gain
C. The AP's antenna gain is lower than the client's antenna gain
D. The client's transmit power is significantly lower than the AP's transmit power
Answer: D

NEW QUESTION: 4

A. SELECT StudentCode as Code, RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
B. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
C. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
D. SELECT StudentCode as Code, DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
E. SELECT StudentCode as Code, NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
F. SELECT Id, Name, Marks, DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank FROM StudentMarks
G. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
Answer: A
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/ms189798.aspx