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NEW QUESTION: 1
Given:
class Snoochy {
Boochy booch;
public Snoochy() { booch = new Boochy(this); }
}
class Boochy {
Snoochy snooch;
public Boochy(Snoochy s) { snooch = s; }
}
And the statements:
21. public static void main(String[] args) {
22. Snoochy snoog = new Snoochy();
23. snoog = null;
24. // more code here
25. }
Which statement is true about the objects referenced by snoog, snooch, and booch immediately after line
23 executes?
A. Only the object referenced by snooch is eligible for garbage collection.
B. Only the object referenced by booch is eligible for garbage collection.
C. Only the object referenced by snoog is eligible for garbage collection.
D. The objects referenced by snooch and booch are eligible for garbage collection.
E. None of these objects are eligible for garbage collection.
Answer: D

NEW QUESTION: 2
You have a 4-node FAS8060 cluster. You are using the vol move command to relocate a volume from an aggregate on node 1 to an aggregate on node 4.
In this scenario, which network is used for the traffic being relocated?
A. the intercluster network
B. the HA interconnect
C. the cluster interconnect
D. the node management network
Answer: C

NEW QUESTION: 3

A. Option C
B. Option A
C. Option D
D. Option B
E. Option E
Answer: A,B,D

NEW QUESTION: 4
웹 애플리케이션은 ELB Application Load Balancer 뒤의 Amazon EC2 인스턴스에서 실행됩니다. 인스턴스는 여러 가용 영역의 EC2 Auto Scaling 그룹에서 실행됩니다.
매일 밤 Auto Scaling 그룹의 크기는 두 배가됩니다. 트래픽 분석에 따르면 특정 지역의 사용자는 EC2 인스턴스에 로컬로 저장된 동일한 정적 컨텐츠를 요청하고 있습니다.
Solutions Architect는 사용자의 애플리케이션 성능을 확장하고 향상시킬 필요성을 어떻게 줄일 수 있습니까?
A. EC2 루트 볼륨 대신 Amazon EFS에 내용을 저장합니다.
B. 요청하는 사용자에게 더 가까운 새 VPC에 응용 프로그램을 다시 배포하십시오.
C. Amazon Redshift를 구현하여 사용자에게 더 가까운 콘텐츠 리포지토리를 만듭니다.
D. 사이트에 대한 Amazon CloudFront 배포를 생성하고 사용자 트래픽을 배포로 리디렉션합니다.
Answer: D
Explanation:
Explanation
https://aws.amazon.com/efs/