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    NEW QUESTION: 1
    質問に答えるために、以下の情報を参照してください。
    組織内のデスクトップコンピュータは同等のセキュリティ環境における再利用のために消毒されました。データが組織のポリシーおよびすべてのマーキングに基づいて破壊され、以前磁気ドライブに保存されたデータの機密性の他の外部兆候は除去しました。
    磁気ドライブは製品の製造業者の指示に従って二回消磁ました後、消磁とセキュリティ上の最も可能性が高い問題は何ですか。
    A. ヒューマンエラーという原因で、第二パス用のチャンバー内で周りのドライブを回すのはできないことです。
    B. メディアを消毒するとき、不適切な記は保持しています。
    C. 市販品は多くの場合、消磁装置の製品で利用可能な磁気力の重大な弱点を持っています。
    D. 消磁装置の製品が適切に維持し、運用することはできません。
    Answer: D

    NEW QUESTION: 2
    カスタムフィールドを削除するとどうなりますか?
    A. フィールドは削除済みリストに表示され、そこから削除を取り消すことができます
    B. フィールドのデータが保存され、フィールドが完全に削除されます
    C. カスタムフィールドは削除できません
    D. フィールドとそのデータは完全に削除されます
    Answer: A

    NEW QUESTION: 3
    Prerequisite:
    A sorted input dataset with record length 100 contains at least one record for each of the values '1', '2', '3'
    in the first byte. The applied sort criteria is 1,100,ch,a.
    Requirements:
    1 .) All records with '1' in the first byte must be ignored.
    2 .) All records with '2' in the first byte must be written to the output dataset.
    3 .) If there is a '3' in the first byte, the read iteration must be left.
    4 .) The program must not abend or loop infinitely.
    If the code below does not fulfill the specifications provided above, which of the following is the most likely
    reason?
    DCL DDIN FILE RECORD INPUT;
    DCL DDOUT FILE RECORD OUTPUT;
    DCL 1 INSTRUC,
    3 A CHAR(1),
    3 * CHAR(99);
    DCL EOF_IN BIT(1) INIT('0'B);
    DCL (Z1,Z2,Z3,ZO) BIN FIXED(31) INIT(0);
    ON ENDFILE(DDIN) EOF_IN = '1'B;
    READ FILE(DDIN) INTO (INSTRUC);
    LOOP: DO WHILE (

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      EOF_IN);
      SELECT(INSTRUC.A);
      WHEN('1') DO;
      Z1 +-= Z1;
      ITERATE LOOP;
      END;
      WHEN('3') DO;
      Z3 = Z3+1;
      LEAVE LOOP;
      END;
      WHEN('2') DO;
      Z2 = Z2+1;
      WRITE FILE(DDOUT) FROM(INSTRUC);
      END;
      OTHER DO;
      ZO = ZO+1;
      PUT SKIP LIST(INSTRUC.A);
      END;
      END;/*select*/
      READ FILE(DDIN) INTO(INSTRUC);
      END ;/*loop*/
      A. The code does not fulfill the requirement because not all records with '2' in the first byte will be written to the output dataset.
      B. The code fulfills the requirement.
      C. The code does not fulfill the requirement because the program will loop infinitely.
      D. The code does not fulfill the requirement because the last record with '2' in the first byte will be written twice to the output dataset.
      Answer: C

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