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NEW QUESTION: 1
View the Exhibit.
Examine the following command that is executed for the TRANSPORT table in the SH schema:
SQL> SELECT DBMS_STATS.CREATE_EXTENDED_STATS('sh', 'customers_obe', '(country_id, cust_state_province)') FROM dual; Which statement describes the significance of this command?
Exhibit:

A. It creates a virtual hidden column in the CUSTOMERS_OBE table.
B. It collects statistics with AUTO_SAMPLE_SIZE for ESTIMATE_PERCENT.
C. It collects statistics into the pending area in the data dictionary.
D. It creates a histogram to hold skewed information about the data in the columns.
Answer: A
Explanation:
Explanation/Reference:
Explanation:
DBMS_STATS.CREATE_EXTENDED_STATS Function
Creates a virtual column for a user specified column group or an expression in a table This function creates a column statistics entry in the system for a user specified column group or an expression in a table. Statistics for this extension will be gathered when user or auto statistics gathering job gathers statistics for the table. We call statistics for such an extension, "extended statistics". This function returns the name of this newly created entry for the extension.

NEW QUESTION: 2
A technician has verified that a recent loss of network connectivity to multiple workstations is due to a bad CAT5 cable in the server room wall. Which of the following tools can be used to locate its physical location within the wall?
A. Multimeter
B. Cable tester
C. Cable certifier
D. Toner probe
Answer: D
Explanation:
Explanation/Reference:
Explanation:
Toner probes are specifically used to trace cables hidden in floors, ceilings, or walls. They can also be used to track cables from the patch panels to their destinations.

NEW QUESTION: 3



A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY OrderAmount DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) DESC) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WHERE Rnk = 1
Answer: A