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    About Service Provider Routing and Switching, Specialist (JNCIS-SP) Exam Questions

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    NEW QUESTION: 1
    Which routing protocols are compatible with stubs. (Choose two)
    A. OSPF
    B. RIP
    C. IS_IS
    D. EGP
    E. EIGRP
    F. BGP
    Answer: A,E

    NEW QUESTION: 2
    Refer to the exhibit.

    Security policy requires all idle-exec sessions to be terminated in 600 seconds. Which configuration achieves this goal?
    A. line vty 0 15
    exec-timeout
    B. line vty 0 4
    exec-timeout 600
    C. line vty 0 15
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    Answer: A

    NEW QUESTION: 3
    A researcher has a sample of 700 observations from a population whose standard deviation is known to be
    1,235.6. The mean of the sample is calculated to be 219.2. The null hypothesis is stated as Ho: mean
    150 and the alternative is non-directional. The p-value in this case equals ________.
    A. 12.82%
    B. 10.16%
    C. 6.94%
    D. 13.88%
    Answer: D
    Explanation:
    Explanation/Reference:
    Explanation:
    The z-statistic under the null equals (219.2 - 150)/(1235.6/(700

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      .5)) = 1.48. Since the alternative is non- directional, you must use a two-tailed test and ask the question, "What is the probability of observing a z- statistic at least as large in magnitude as 1.48?" The answer to this will give you the p- value for this sample under the two-tailed test. The right-tailed probability of observing a z-statistic which is at least as big as 1.48 equals 1.0 - 0.9306 = 0.0694 = 6.94%. The left-tailed probability of observing a z-statistic which is at least as small as - 1.48 also equals 6.94% since the standard normal distribution is symmetrical about zero. Therefore, the p-value of this two-tailed test in this sample equals 6.94%*2 = 13.88%.

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