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NEW QUESTION: 1
ペネトレーションテスターは、低い権限でWindowsホストを悪用し、次の権限を持つディレクトリを見つけました。


特権をエスカレートするには、次のうちどれを実行する必要がありますか？
A. カーベロアスト
B. シェルの別のプロセスへの移行
C. 書き込み可能なサービス
D. SAMデータベースの取得
Answer: B

NEW QUESTION: 2
Your company has a main office and a branch office. The relevant portion of the network is configured as shown in the exhibit. (Click the Exhibit button.)
In the branch office, you deploy a new computer named Computer1 that runs Windows 7. You need to assign an IP address to Computer1.
Which IP address should you use?
Exhibit:

A. 192.168.2.40
B. 192.168.2.30
C. 192.168.2.65
D. 192.168.2.63
Answer: A
Explanation:
Internal IP Adress of router is 192.168.2.62/27 Leaves 5 bits for range = 32 addresses (including the 2 reserved addresses) Subnet Mask = 255.255.255.224
Address: 192.168.2.62 11000000.10101000.00000010.001 11110
Netmask: 255.255.255.224 = 27 11111111.11111111.11111111.111 00000
Wildcard: 0.0.0.31 00000000.00000000.00000000.000 11111
Network: 192.168.2.32/27 11000000.10101000.00000010.001 00000
Network Address : 192.168.2.32 (reserved)
Address of First Host : 192.168.2.33
Address of Last Host : 192.168.2.62
Broadcast Address : 192.168.2.63 (reserved)
Acceptable IP range: 192.168.2.33 -192.168.2.62
Therefore
192.168.2.30: is out of range (in the wrong subnet, not subnet 2).
192.168.2.40: is accepable (in correct subnet, and not reservered).
192.168.2.63: is reserved for Broadcast (in subnet, but reservered).
192.168.2.65: is out of range (in the wrong subnet, not subnet 2).
Accepable IP ranges for those interested(excluding the 2 reserved IP addersses): Segment 1: 192.168.2.1 -192.168.2.30 Segment 2: 192.168.2.33 -192.168.2.62 Segment 3: 192.168.2.65 -192.168.2.94 Segment 4: 192.168.2.97 -192.168.2.126 Segment 5: 192.168.2.129 -192.168.2.158 Segment 6: 192.168.2.161 -192.168.2.190 Segment 7: 192.168.2.193 -192.168.2.222 Segment 8: 192.168.2.225 -192.168.2.254
Segments for those interested(including the 2 reserved IP addersses): Segment 1: 192.168.2.0 -192.168.2.31 Segment 2: 192.168.2.32 -192.168.2.63 Segment 3: 192.168.2.64 -192.168.2.95 Segment 4: 192.168.2.96 -192.168.2.127 Segment 5: 192.168.2.128 -192.168.2.159 Segment 6: 192.168.2.160 -192.168.2.191 Segment 7: 192.168.2.192 -192.168.2.223 Segment 8: 192.168.2.224 -192.168.2.255

NEW QUESTION: 3
Aggregate global IPv6 addresses begin with which bit pattern in the first 16-bit group?
A. 011/2
B. 001/3
C. 010/2
D. 000/3
Answer: B