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NEW QUESTION: 1
会社がDynamics 365 Financeを購入します。
会社が実装できる2つの機能はどれですか。正しい選択ごとに完全なソリューションが提示されます。
注：それぞれの正しい選択は1ポイントの価値があります。
A. オムニチャネル
B. 総勘定元帳
C. 製造
D. 支払い詐欺防止
E. 売掛金
Answer: B,E

NEW QUESTION: 2
A company hosts virtual machines (VMs) in an on-premises datacenter and in Azure. The on-premises and Azure-based VMs communicate using ExpressRoute.
The company wants to be able to continue regular operations if the ExpressRoute connection fails.
Failover connections must use the Internet and must not require Multiprotocol Label Switching (MPLS) support.
You need to recommend a solution that provides continued operations.
What should you recommend?
A. Increase the bandwidth for the on-premises internet connection.
B. Set up a second ExpressRoute connection.
C. Increase the bandwidth of the existing ExpressRoute connection.
D. Set up a VPN connection.
Answer: D
Explanation:
Explanation/Reference:
References:
https://docs.microsoft.com/en-us/azure/architecture/reference-architectures/hybrid-networking/ expressroute-vpn-failover

NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

You need to determine the total number of customers who have only loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT (DISTINCT CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE
B. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT
CustNoFROM tblLoanAcct) R
C. CustNo = L.CustNo
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT
CustNoFROM tblLoanAcct) R
E. CustNo
F. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo =
G. CustNo IS NULL
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT
CustNoFROM tblLoanAcct) R
I. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct
DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR
J. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT
AcctNoFROM tblLoanAcct) R
K. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN
tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
Answer: K
Explanation:
The RIGHT JOIN keyword returns all records from the right table (table2), and the matched records from the left table (table1). The result is NULL from the left side, when there is no match.
References: https://www.w3schools.com/sql/sql_join_right.asp