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NEW QUESTION: 1
You have two servers named Server1 and Server2 that run Windows Server 2016.
Server1 contains a volume named Volume1.
You implement a Storage Replica that replicates the contents of Volume1 from Server1 to Server2.
Server1 fails.
From Server2, you need to ensure that you can access the contents of Volume1.
What should you run?
A. Clear-FileStorageTier
B. vssadmin revert shadow
C. Update-StoragePool
D. Set-SRPartnership
Answer: D
Explanation:
Explanation/Reference:
Explanation:
We need to promote the destination volume to become the source volume.
Reference:
https://docs.microsoft.com/en-us/windows-server/storage/storage-replica/storage-replica-frequently-asked- questions

NEW QUESTION: 2
개요
시험의 다음 섹션은 실습입니다. 이 섹션에서는 실제 환경에서 일련의 작업을 수행합니다. 실제 환경에서와 같이 대부분의 기능을 사용할 수 있지만 일부 기능 (예 : 복사 및 붙여 넣기, 외부 웹 사이트 탐색 기능)은 의도적으로 설계 할 수 없습니다.
채점은 실험실에 명시된 작업을 수행 한 결과를 기반으로 합니다. 즉, 작업을 수행하는 방법은 중요하지 않습니다. 작업을 성공적으로 수행하면 해당 작업에 대한 크레딧을 얻게 됩니다.
실습 시간은 별도로 정해져 있지 않으며 이 시험에는 두 개 이상의 실습 과정이 있어야 합니다. 각 실습을 마치는데 시간을 많이 사용할 수 있습니다. 그러나 제공된 시간 내에 실험실 및 시험의 다른 모든 섹션을 완료할 수 있도록 시간을 적절히 관리해야 합니다.
랩 내에서 다음 버튼을 클릭하여 작업을 제출하면 랩으로 돌아올 수 없습니다.
실습을 시작하려면
다음 버튼을 클릭하여 실습을 시작할 수 있습니다.
회사는 공개 웹 사이트에 여러 문서를 저장할 계획입니다.
storagelod8095859 스토리지 계정에서 문서를 호스팅 할 bios라는 컨테이너를 작성해야 합니다. 솔루션은 익명 액세스를 보장해야 하며 사용자가 컨테이너의 폴더를 찾아 볼 수 있어야 합니다.
Azure Portal에서 무엇을 해야 합니까?
Answer:
Explanation:
See explanation below.
Explanation
Azure portal create public container
To create a container in the Azure portal, follow these steps:
Step 1. Navigate to your new storage account in the Azure portal.
Step 2. In the left menu for the storage account, scroll to the lob service section, then select Blobs.
Select the + Container button.
Type a name for your new container: bios
Set the level of public access to the container: Select anonymous access.

Step 3. Select OK to create the container.
References:
https://docs.microsoft.com/en-us/azure/storage/blobs/storage-quickstart-blobs-portal

NEW QUESTION: 3
What is defined as the rules for communicating between computers on a Local Area Network (LAN)?
A. LAN transmission methods
B. LAN topologies
C. Contention Access Control
D. LAN Media Access methods
Answer: D
Explanation:
Media contention occurs when two or more network devices have data to send at the same time. Because multiple devices cannot talk on the network simultaneously, some type of method must be used to allow one device access to the network media at a time. This is done in two main ways: carrier sense multiple access collision detect (CSMA/CD) and token passing.
In networks using CSMA/CD technology such as Ethernet, network devices contend for the network media. When a device has data to send, it first listens to see if any other device is currently using the network. If not, it starts sending its data. After finishing its transmission, it listens again to see if a collision occurred. A collision occurs when two devices send data simultaneously. When a collision happens, each device waits a random length of time before resending its data. In most cases, a collision will not occur again between the two devices. Because of this type of network contention, the busier a network becomes, the more collisions occur. This is why performance of Ethernet degrades rapidly as the number of devices on a single network increases. In token-passing networks such as Token Ring and FDDI, a special network frame called a token is passed around the network from device to device. When a device has data to send, it must wait until it has the token and then sends its data. When the data transmission is complete, the token is released so that other devices may use the network media. The main advantage of token-passing networks is that they are deterministic. In other words, it is easy to calculate the maximum time that will pass before a device has the opportunity to send data. This explains the popularity of token-passing networks in some real-time environments such as factories, where machinery must be capable of communicating at a determinable interval. For CSMA/CD networks, switches segment the network into multiple collision domains. This reduces the number of devices per network segment that must contend for the media. By creating smaller collision domains, the performance of a network can be increased significantly without requiring addressing changes.
The following are incorrect answers: LAN topologies: Think of a topology as a network's virtual shape or structure. This shape does not necessarily correspond to the actual physical layout of the devices on the network. For example, the computers on a home LAN may be arranged in a circle in a family room, but it would be highly unlikely to find a ring topology there. Common topologies are: bus, ring, star or meshed. See THIS LINK for more information. LAN transmission methods: refer to the way packets are sent on the network and are either unicast, multicast or broadcast. See THIS LINK for more information. Contention Access Control: This is a bogus detractor. Contention is a real term but Contention Access Control is just made up. Contention methods is very closely related to Media Access Control methods. In communication networks, contention is a media access method that is used to share a broadcast medium. In contention, any computer in the network can transmit data at any time (first come-first served). This system breaks down when two computers attempt to transmit at the same time. This is a case of collision. To avoid collision, carrier sensing mechanism is used. Here each computer listens to the network before attempting to transmit. If the network is busy, it waits until network quiets down. In carrier detection, computers continue to listen to the network as they transmit. If computer detects another signal that interferes with the signal it is sending, it stops transmitting. Both computers then wait for random amount of time and attempt to transmit. Contention methods are most popular media access control method on LANs.
Reference(s) used for this question: http://docwiki.cisco.com/wiki/Introduction_to_LAN_Protocols#LAN_Media-Access_Methods
http://en.wikipedia.org/wiki/Contention_%28telecommunications%29

NEW QUESTION: 4
What is the result in Array after the following code has executed?

A. A 1-D array of {1, 8, 0, 1, 2, 3, 4, 6, 2}
B. A 1-D array of {1, 8, 0, 1, 2, 2, 9}
C. A 1-D array of {1, 4, 3, 2, 1, 0}
D. A 1-D array of {1, 4, 3, 2, 1, 0, 8, 6, 2}
Answer: D