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NEW QUESTION: 1
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, bei denen die gleichen oder ähnliche Antwortmöglichkeiten verwendet werden. Eine Antwortauswahl kann für mehr als eine Frage in der Reihe richtig sein. Jede Frage ist unabhängig von den anderen Fragen in dieser Reihe. In einer Frage angegebene Informationen und Details gelten für diese Frage.
Sie haben eine Datenbank für ein Bankensystem. Die Datenbank enthält zwei Tabellen mit den Namen tblDepositAcct und tblLoanAcct, in denen Einlagen- und Darlehenskonten gespeichert sind. Beide Tabellen enthalten folgende Spalten:

Sie müssen die Gesamtzahl der Kunden ermitteln, die entweder Einlagenkonten oder Darlehenskonten haben, jedoch nicht beide Kontotypen.
Welche Transact-SQL-Anweisung sollten Sie ausführen?
A. SELECT COUNT (DISTINCT L.CustNo) VON tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
B. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
C. SELECT COUNT (*) FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
D. SELECT COUNT (DISTINCT COALESCE (D.CustNo, L.CustNo)) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWhere
E. SELECT COUNT (*) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
F. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT (DISTINCT D.CustNo) FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
H. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
Answer: D
Explanation:
Erläuterung
SQL Server stellt den vollständigen Outer-Join-Operator FULL OUTER JOIN bereit, der alle Zeilen aus beiden Tabellen enthält, unabhängig davon, ob die andere Tabelle einen übereinstimmenden Wert hat oder nicht.
Betrachten Sie einen Join der Product-Tabelle und der SalesOrderDetail-Tabelle in ihren ProductID-Spalten. Die Ergebnisse zeigen nur die Produkte mit Kundenaufträgen. Der Operator ISO FULL OUTER JOIN gibt an, dass alle Zeilen aus beiden Tabellen in die Ergebnisse einbezogen werden sollen, unabhängig davon, ob die Tabellen übereinstimmende Daten enthalten.
Sie können eine WHERE-Klausel mit einem vollständigen Outer-Join einfügen, um nur die Zeilen zurückzugeben, bei denen keine übereinstimmenden Daten zwischen den Tabellen vorhanden sind. Die folgende Abfrage gibt nur die Produkte zurück, die keine übereinstimmenden Kundenaufträge haben, sowie die Kundenaufträge, die nicht mit einem Produkt übereinstimmen.
USE AdventureWorks2008R2;
GEHEN
- Das Schlüsselwort OUTER nach dem Schlüsselwort FULL ist optional.
SELECT p.Name, sod.SalesOrderID
AB Produktion.Produkt p
VOLLSTÄNDIGE AUSSENVERBINDUNG Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IST NULL
OR sod.ProductID IS NULL
ORDER BY p.Name;
Referenzen: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx

NEW QUESTION: 2
You are a database developer of a Microsoft SQL Server 2012 database. You are designing a table that will store Customer data from different sources. The table will include a column that contains the CustomerID from the source system and a column that contains the SourceID. A sample of this data is as shown in the following table. You need to ensure that the table has no duplicate CustomerID within a SourceID. You also need to ensure that the data in the table is in the order of SourceID and then CustomerID.
Which Transact- SQL statement should you use?
A. CREATE TABLE Customer(SourceID int NOT NULL IDENTITY,CustomerID int NOT NULL IDENTITY,CustomerName varchar(255) NOT NULL);
B. CREATE TABLE Customer(SourceID int NOT NULL PRIMARY KEY CLUSTERED,CustomerID int NOT NULL UNIQUE,CustomerName varchar(255) NOT NULL);
C. CREATE TABLE Customer(SourceID int NOT NULL,CustomerID int NOT NULL PRIMARY KEY CLUSTERED,CustomerName varchar(255) NOT NULL);
D. CREATE TABLE Customer(SourceID int NOT NULL,CustomerID int NOT NULL,CustomerName varchar(255) NOT NULL,CONSTRAINT PK_Customer PRIMARY KEY CLUSTERED(SourceID, CustomerID));
Answer: D
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 3
When upgrading from Samba 2 to Samba 3, which of the following point should be considered when user information is stored in a LDAP server? (Select TWO correct answers)
A. Set the domain SID of Samba 3 to the same value of Samba 2 with the net setlocalsid command
B. Convert all passwords in the LDAP server to the new encryption method
C. Change the permissions of the files created by Samba 2 to match the group permissions in Samba 3
D. Dump all data files created by Samba 2 and restore them with Samba 3 to fix the ACLs
E. Never run the Samba 3 server before the configuration to use the LDAP server is complete
Answer: A,E

NEW QUESTION: 4
大規模なオンプレミスのOpenStack環境を持つ企業の管理チームは、非実稼働ワークロードをAWSに移行したいと考えています。 AWS Direct Connect接続がプロビジョニングされ、環境を接続するように設定されました。契約上の義務により、実稼働ワークロードはオンプレミスのままである必要があり、次の契約交渉後にAWSに移動されます。同社は、イメージを強化するためのインターネットセキュリティセンター（CIS）標準に準拠しています。この構成は、会社の構成管理システムを使用して開発されました。
どのソリューションが、AWS環境で大きなオーバーヘッドなしに同一のイメージを自動的に作成しますか？
A. コンソールにログインし、Amazon EC2インスタンスを起動して、構成管理エージェントをインストールします。
構成管理システムを介して変更が適用されたら、コンソールにログインし、インスタンスから新しいAMIを作成します。
B. 構成管理システムで変更が行われると、Jenkinsのジョブがトリガーされ、VM Importコマンドを使用してAmazon VPCにAmazon EC2インスタンスが作成されます。ライフサイクルフックを使用してAWS Lambda関数を起動し、AMIを作成します。
C. Amazon EC2インスタンスを作成するAWS CloudFormationテンプレートを作成します。 cloud-unitを使用して構成管理エージェントをインストールし、cfn-waitを使用して構成管理が正常に適用されるまで待機し、AWS Lambda-backedカスタムリソースを使用してAMIを作成します。
D. 新しいAWS OpsWorksレイヤーを作成し、イメージ強化標準をミラーリングします。このレイヤーをすべてのAWSワークロードのベースラインとして使用します。
Answer: C