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NEW QUESTION: 1
A. The service consumer's request message containing the ID value can be encrypted by inserting the private key of the service consumer into the data. Because all service consumers have different private keys, this approach will lead to different encrypted values, even if the plain text ID values are the same. As a result, two data items with the same encrypted unique identifier cannot exist.
B. The database rules are changed so that the ID value of database records no longer needs to be unique. As a further precaution, the Service A logic is changed to disallow the update of private database records by service consumers with only public access permissions.
C. When Service A detects that a service consumer with public access permissions has submitted an ID value that already exists within a private database record, it stores the service consumer's ID value in a temporary database and returns a response message indicating that the update was successful. A notification message is then sent to a human database administrator who manually contacts the owner of the service consumer in order to explain that the ID value submitted cannot be accepted because it already exists within a private database record.
D. Each record in Database A is classified as either private or public. After Service A is invoked by a service consumer (1), it authenticates the request message using an identity store and retrieves the corresponding authorization (2, 3). Once authorized, the service consumer's request is submitted to Database A (4), which then returns the requested data (5) If the service consumer has private access permissions, all of the returned data is included in Service A's response message (6). If the service consumer has public access permissions, then Service A first filters the data in order to remove all unauthorized private data records before sending to the response message to the service consumer (6).

In addition to retrieving data, Service A's data access capability can be used to update database records. An investigation recently revealed an information leakage problem that can occur when service consumers with public access permissions attempt to update the ID value of a database record The ID values of all database records (private or public) must be unique. When a service consumer with public access permissions updates a public database record with an ID value that is already assigned to a private database record, the database returns an error message describing this conflict. This error text reveals confidential information by stating that the ID value submitted by the service consumer with public access permissions already exists within a private database record.
What steps can be taken to avoid this problem while preserving the requirement that all database records (private and public) have unique ID values?
E. The Exception Shielding pattern is applied to replace the error description text before a response message is returned to the service consumer. Furthermore, the ID value of all database records is appended with a code indicating whether the database record is private or public
Answer: D,E
NEW QUESTION: 2
Troubleshoot command for NGIPSv, i chose the first one. I think i got this one correct
A. system generate-troubleshoot all
B. sudo sf_troubleshoot.pl
Answer: A
NEW QUESTION: 3
展示を参照してください。

HOルーターとBRルーターの間にGREトンネルが作成されました。
HQルーターのトンネルIPとは何ですか?
A. 209.165.202.134
B. 10.111.111.2
C. 209.165.202.130
D. 10.111.111.1
Answer: D
Explanation:
Explanation
In the above output, the IP address of "209.165.202.130" is the tunnel source IP while the IP 10.111.1.1 is the tunnel IP address.
An example of configuring GRE tunnel is shown below:

NEW QUESTION: 4



Get -VM | Stop-VM
Get -VM | Update-VMVersion
Get -VM | Start-VM


Answer:
Explanation:

Explanation
You can configure VM1 as an encryption-supported virtual machine: Yes
You can configure VM2 as an encryption-supported virtual machine: Yes
You can configure VM3 as an encryption-supported virtual machine: Yes
After the "Update-VMVersion" is executed against all three virtual machines, they become:-VM1 Generation
2 Version 8VM2 Generation 1 Version 8 Pay attention to VM2, and the question has not mention to use TPM protector. You can configure this VM asEncryption Supported by using a Key Storage Driveadded to the virtual machine setting.

Within the guest, there is no Virtual TPM

Then , start Encrypt the C system drive with the guest 2012R2 bitlocker feature

After the encryption is completed:-
