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APM APM-PMQ exam
  • Exam Code: APM-PMQ
  • Exam Name: APM Project Management Qualification (PMQ) Exam
  • Version: V12.35
  • Q & A: 70 Questions and Answers
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NEW QUESTION: 1
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

You need to determine the total number of customers who have either deposit accounts or loan accounts, but not both types of accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(DISTINCT L.CustNo)
FROM tblDepositAcct D
RIGHT JOIN tblLoanAcct L ON D.CustNo =L.CustNo
WHERE D.CustNo IS NULL
B. SELECT COUNT(*)
FROM (SELECT AcctNo
FROM tblDepositAcct
INTERSECT
SELECT AcctNo
FROM tblLoanAcct) R
C. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))
FROM tblDepositAcct D
FULL JOIN tblLoanAcct L ON D.CustNo =L.CustNo
WHERE D.CustNo IS NULL OR L.CustNo IS NULL
D. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
UNION
SELECT CustNo
FROM tblLoanAcct) R
E. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
UNION ALL
SELECT CustNo
FROM tblLoanAcct) R
F. SELECT COUNT(*)
FROM tblDepositAcct D
FULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
G. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
EXCEPT
SELECT CustNo
FROM tblLoanAcct) R
H. SELECT COUNT (DISTINCT D.CustNo)
FROM tblDepositAcct D, tblLoanAcct L
WHERE D.CustNo = L.CustNo
Answer: C
Explanation:
Explanation/Reference:
Explanation:
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx

NEW QUESTION: 2
Which of the following is a task of the "Test Analysis and Design" activity of the test process?
A. Verifying that the test environment has been set up correctly
B. Checking test logs against the exit criteria specified in test planning
C. Identifying necessary test data to support the test conditions and test cases
D. Measuring the percentage of prepared test cases with what was actually prepared
Answer: C
Explanation:
Section: (none)

NEW QUESTION: 3
You configure the Diagnostics settings for an Azure SQL database as shown in the following exhibit.

Use the drop-down menus to select the answer choice that completes each statement based on the information presented in the graphic.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation


NEW QUESTION: 4
Microsoft 365サブスクリプションがあります。
次の展示に示すように、Label1という名前の保持ラベルを作成します。

Label1をSharePointサイトに公開します。
ドロップダウンメニューを使用して、図に示されている情報に基づいて各ステートメントを完成させる回答の選択肢を選択します。
注:それぞれの正しい選択には1ポイントの価値があります。

Answer:
Explanation:

Explanation

References:
https://docs.microsoft.com/en-us/office365/securitycompliance/labels

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