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NEW QUESTION: 1
Note: This question is part of a series of questions that use the same scenario. For your convenience, the scenario is repeated in each question. Each question presents a different goal and answer choices, but the text of the scenario is exactly the same in each question on this series.
You have a database that tracks orders and deliveries for customers in North America. System versioning is enabled for all tables. The database contains the Sales.Customers, Application.Cities, and Sales.CustomerCategories tables.
Details for the Sales.Customers table are shown in the following table:

Details for the Application.Cities table are shown in the following table:

Details for the Sales.CustomerCategories table are shown in the following table:

You need to create a query that meets the following requirements:
- For customers that are not on a credit hold, return the CustomerID and the latest recorded population for the delivery city that is associated with the customer.
- For customers that are on a credit hold, return the CustomerID and the latest recorded population for the postal city that is associated with the customer.
Which two Transact-SQL queries will achieve the goal? Each correct answer presents a complete solution.

A. Option D
B. Option A
C. Option B
D. Option C
Answer: B,C
Explanation:
Using Cross Joins
A cross join that does not have a WHERE clause produces the Cartesian product of the tables involved in the join. The size of a Cartesian product result set is the number of rows in the first table multiplied by the number of rows in the second table.
However, if a WHERE clause is added, the cross join behaves as an inner join.
B: You can use the IIF in the ON-statement.
IIF returns one of two values, depending on whether the Boolean expression evaluates to true or false in SQL Server.
References:
https://technet.microsoft.com/en-us/library/ms190690(v=sql.105).aspx
https://msdn.microsoft.com/en-us/library/hh213574.aspx

NEW QUESTION: 2
PVLANのコミュニティポートの特徴はどれですか？
A. プロミスキャスポートと通信できます
B. 独立したポートと通信できます
C. 同じコミュニティ内の他のコミュニティポートと通信することはできません。
D. レイヤ3で他のすべてのポートから分離されています
Answer: A

NEW QUESTION: 3
Refer to the exhibit.

Which statement is true?
A. OSPF neighbor 192.168.158.103 is ineligible to be selected as the designated router.
B. OSPF neighbor 192.168.158.103 is least likely to be selected as the designated router.
C. OSPF neighbor 192.168.158.103 is second most likely to be selected as the designated router.
D. OSPF neighbor 192.168.158.103 is most likely to be selected as the designated router.
Answer: B