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NEW QUESTION: 1
Which two different configurations can you apply to a device incoming SSH access? (Choose two)
A. ipv6 access-list VTY-ACCESS-IN secuence 10 deny tcp any any eq 22 sequence 20 permit ipv6 any any line vty 0 15 ipv6 access-class VTY-ACCESS-IN in
B. ipv6 access-list VTY-ACCESS-IN secuence 10 deny tcp any any eq 22 sequence 20 permit ipv6 any any interface Ethernet0/0 ip traffic-filter VTY-ACCESS-IN out
C. ipv6 access-list VTY-ACCESS-IN secuence 10 deny tcp any any eq 22 sequence 20 permit ipv6 any any line vty 0 15 ipv6 access-list VTY-ACCESS-IN out
D. ipv6 access-list VTY-ACCESS-IN secuence 10 deny tcp any any eq 22 sequence 20 permit ipv6 any any interface Ethernet0/0 ipv6 traffic-filter VTY-ACCESS-IN in
E. ipv6 access-list VTY-ACCESS-IN secuence 10 deny tcp any any eq 22 sequence 20 permit ipv6 any any interface Ethernet0/0 ipv6 traffic-filter VTY-ACCESS-IN out
Answer: A,D
NEW QUESTION: 2
The ANSI X9.52 standard defines a variant of DES encryption with keys
k1, k2, and k3 as:
C = Ek3 [Dk2 [Ek1 [M]]]
What is this DES variant?
A. Triple DES in theEDE mode
B. Double DES with an encryption and decryption with different keys
C. Triple DES in the EEE mode
D. DESX
Answer: A
Explanation:
This version of triple DES performs an encryption (E) of plaintext
message M with key k1, a decryption (D) with key k2 (essentially,
another encryption), and a third encryption with key k3. Another
implementation of DES EDE is accomplished with keys k1 and k2
being independent, but with keys k1 and k3 being identical. This
implementation of triple DES is written as:
C = Ek1 [Dk2 [Ek1 [M]]]
Answer a is incorrect since, in DESX, input plaintext is bitwise
XORed with 64 bits of additional key material before encryption
with DES, and the output of DES is also bitwise XORed with
another 64 bits of key material. Answer b, DES in the EEE, mode is
written as:
C = Ek3 [Ek2 [Ek1 [M]]]
where three consecutive encryptions are performed on plaintext
message, M, with three independent keys, k1, k2, k3.
Answer c is incorrect since the question contains three encryptions.
Implementing two DES encryptions does not provide the
additional security anticipated over a single DES encryption because
of the meet-in-the-middle attack. Consider a DES cipher with a key
size of p. A double encryption will result in an effective key size of
2p and yield the final result R. Thus, one would anticipate that one
would have to search a key space of 22p in an exhaustive search of
the keys. However, it can be shown that a search of the key space on
the order of 2p is all that is necessary. This search is the same size as required for a single DES encryption. This situation is illustrated as follows:
The sequences shown illustrate the first DES encryption of a
plaintext message M with all keys k1 through k2p yielding the
intermediate encrypted results C1 through C2p.
Ek1 [M] C1
Ek2 [M] C2
Ek2p [M] C2p
If we have available ciphertext R where R = Ek2 [Ek1 [M]] for a pair of secret keys k1 and k2, for each key m there is only one key k such that
Dm[R] = Ek[M] where D is the decipherment of R back from the second
DES encipherment. In other words, there are 2p possible keys that will
result in the pair [M,R] and, thus, can be found in a search of order 2p.
NEW QUESTION: 3
DRAG DROP


Answer:
Explanation:
Run the system setup wizard = step 1
Add an authentication realm = step 2
Configure identity management = step 3
Configure directory groups = step 4
https://www.cisco.com/c/dam/en/us/products/collateral/security/cloud-web-security/cws_wsa_wsav.pdf
NEW QUESTION: 4
When comparing host based IDS with network based ID, which of the following is an obvious advantage?
A. It is unaffected by switched networks.
B. It cannot analyze encrypted information.
C. It is not costly to setup.
D. It is not costly to manage.
Answer: A
Explanation:
Host-based IDSs are unaffected by switched networks. When Host-based IDSs operate on OS audit trails, they can help detect Trojan horse or other attacks that involve software integrity breaches. These appear as inconsistencies in process execution.