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NEW QUESTION: 1
The Component Processor's flow can be used to simulate a looping construct. In which event would a PeopleCode program designed to take advantage of this feature be placed?
A. FieldDefault
B. PreBuild
C. SearchInit
D. RowInit
E. PostBuild
F. FieldFormula
Answer: D
NEW QUESTION: 2
はいまたはいいえ:ビューの寸法の数を増やすと、マークの数が増えます
A. はい
B. いいえ
Answer: A
Explanation:
Explanation
Of course! As an example, see below:
1) Using the Sample Superstore data, let's plot a bar chart showing the Sales for each Category:

Observe that we have 3 marks - Each bar in a bar chart is called a mark. Similarly, each point in a scatter plot is also a mark , and so on for all charts.
1 row by 3 columns means that clearly on the y-axis (Sales), we have only a single mark - a single continous axis, but 3 different marks (Technology, Furniture and Office supplies ) on the x-axis.
2) Now let's add subcategory to the view as well (another dimension):

Observe that the number of marks has increased - i.e the number of Bars.
Also, notice we now have 1 row and 17 columns. Simply because 1 row = Sales (on the y-axis), and on the x-axis, we have 17 different columns (i.e product sub categories!!)
NEW QUESTION: 3
AWS Key Management Service(AWS KMS)は、データの暗号化に使用される暗号化キーを簡単に作成および制御できるマネージドサービスです。 AWS KMSは、Amazon EBS、Amazon S3、Amazon Redshift、Elastic Transcoder、Amazon WorkMail、Amazon RDSなどの他のAWSサービスと統合されており、管理する暗号化キーでデータを簡単に暗号化できます。 AWS KMSはAWS CloudTrailとも統合されており、規制やコンプライアンスのニーズを満たすのに役立つ主要な使用ログを提供します。 AWS KMSで現在サポートされている暗号化キーのタイプは次のうちどれですか?
A. 秘密の一時鍵契約暗号化
B. 対称および非対称の乱数生成キー暗号化
C. 対称鍵暗号化のみ
D. 非対称キー暗号化と対称キー暗号化
Answer: C
Explanation:
説明
AWS Key Management Service(AWS KMS)は、データの暗号化に使用される暗号化キーを簡単に作成および制御できるマネージドサービスです。 AWS KMSは、Amazon EBS、Amazon S3、Amazon Redshift、Elastic Transcoder、Amazon WorkMail、Amazon RDSなどの他のAWSサービスと統合されており、管理する暗号化キーでデータを簡単に暗号化できます。 AWS KMSはAWS CloudTrailとも統合されており、規制やコンプライアンスのニーズを満たすのに役立つ主要な使用ログを提供します。 AWS KMSは現在、対称(プライベート)キー暗号化のみをサポートしています。
参照:
NEW QUESTION: 4
Which of the following will allow you to have multiple plots on a Waveform Graph?
A. Bundle two 1D arrays of X and Y data together for each plot. Then build an array of these clusters and wire it to the Waveform Graph indicator.
B. Build an n-dimensional array of data with each plot in a separate row (or column) in the array, then wire the array to the Waveform Graph indicator.
C. Both B, and C.
D. Bundle the elements of each waveform into a cluster and build an array of these clusters, then wire the array to the Waveform Graph indicator.
Answer: C