2025 FCP_FGT_AD-7.6 Fragen Und Antworten, FCP_FGT_AD-7.6 Zertifikatsdemo & FCP - FortiGate 7.6 Administrator Prüfungs - Hospital

Fortinet FCP_FGT_AD-7.6 exam
  • Exam Code: FCP_FGT_AD-7.6
  • Exam Name: FCP - FortiGate 7.6 Administrator
  • Version: V12.35
  • Q & A: 70 Questions and Answers
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NEW QUESTION: 1
Your network contains an Active Directory domain named contoso.com. The domain contains a file server named Server1 that runs Windows Server 2012 R2.
You view the effective policy settings of Server1 as shown in the exhibit. (Click the Exhibit button.)

You need to ensure that an entry is added to the event log whenever a local user account is created or deleted on Server1.
What should you do?
A. In Servers GPO, modify the Advanced Audit Configuration settings.
B. In Servers GPO, modify the Audit Policy settings.
C. On Server1, attach a task to the security log.
D. On Server1, attach a task to the system log.
Answer: A
Explanation:
When you use Advanced Audit Policy Configuration settings, you need to confirm that these settings are not overwritten by basic audit policy settings. The following procedure shows how to prevent conflicts by blocking the application of any basic audit policy settings.
Enabling Advanced Audit Policy Configuration
Basic and advanced audit policy configurations should not be mixed. As such, it's best practice to enable Audit: Force audit policy subcategory settings (Windows Vista or later) to override audit policy category settings in Group Policy to make sure that basic auditing is
disabled. The setting can be found under Computer Configuration\Policies\Security
Settings\Local Policies\Security Options, and sets the SCENoApplyLegacyAuditPolicy
registry key to prevent basic auditing being applied using Group Policy and the Local
Security Policy MMC snap-in.
In Windows 7 and Windows Server 2008 R2, the number of audit settings for which
success and failure can be tracked has increased to 53. Previously, there were nine basic
auditing settings under Computer Configuration\Policies\Windows Settings\Security
Settings\Local Policies\Audit Policy. These 53 new settings allow you to select only the
behaviors that you want to monitor and exclude audit results for behaviors that are of little
or no concern to you, or behaviors that create an excessive number of log entries. In
addition, because Windows 7 and Windows Server 2008 R2 security audit policy can be
applied by using domain Group Policy, audit policy settings can be modified, tested, and
deployed to selected users and groups with relative simplicity.
Audit Policy settings
Any changes to user account and resource permissions.
Any failed attempts for user logon.
Any failed attempts for resource access.
Any modification to the system files.
Advanced Audit Configuration Settings
Audit compliance with important business-related and security-related rules by tracking
precisely defined activities, such as:
- A group administrator has modified settings or data on servers that contain finance
information.
- An employee within a defined group has accessed an important file.
- The correct system access control list (SACL) is applied to every file and folder or
registry key on a computer or file share as a verifiable safeguard against
undetected access.
In Servers GPO, modify the Audit Policy settings - enabling audit account management setting will generate events about account creation, deletion and so on.
Advanced Audit Configuration Settings Advanced Audit Configuration Settings ->Audit Policy -> Account Management -> Audit User Account Management In Servers GPO, modify the Audit Policy settings - enabling audit account management setting will generate events about account creation, deletion and so on.


Reference:
http: //blogs. technet. com/b/abizerh/archive/2010/05/27/tracing-down-user-and-computeraccount-deletion-in-active-directory. aspx http: //technet. microsoft. com/en-us/library/dd772623%28v=ws. 10%29. aspx
http: //technet. microsoft. com/en-us/library/jj852202(v=ws. 10). aspx http: //www. petri. co. il/enable-advanced-audit-policy-configuration-windows-server. htm http: //technet. microsoft. com/en-us/library/dd408940%28v=ws. 10%29. aspx http: //technet. microsoft. com/en-us/library/dd408940%28v=ws. 10%29.
aspx#BKMK_step2

NEW QUESTION: 2
You need to configure Server1 to meet the cloud infrastructure requirements.
What should you do?
A. Create a storage space and use the mirror resiliency type.
B. Reinstall VMM.
C. Install the Storage Replica feature.
D. Create a mirrored volume.
Answer: C
Explanation:
Storage Replica (SR) is a new feature that enables storage-agnostic, block-level, synchronous replication between
servers for disaster recovery, as well as stretching of a failover cluster for high availability. Synchronous replication
enables mirroring of data in physical sites with crash-consistent volumes ensuring zero data loss at the file system
level. Asynchronous replication allows site extension beyond metropolitan ranges with the possibility of data loss.
Scenario:
* Server1 is in a private cloud in the Seattle Office
* Infrastructrure requirements include:
Ensure that all of the private cloud components are highly available.
Reference: Getting started with Storage Replica in Windows Server Technical Preview
http://blogs.technet.com/b/craigf/archive/2014/10/04/getting-started-with-storage-replica-in-windows-server-
technical-preview.aspx

NEW QUESTION: 3
The realized mean monthly return on the S&P 500 in the 1990's appears to have been substantially different than the mean return in 2000's. The data indicate that assuming equal population variances is not unreasonable.

u = 1990's population mean return and u = 2000's population mean return. The decision made in this
1 2
hypothesis is (assume at the 10% level):
A. to reject the null hypothesis.
B. not to reject the null hypothesis.
C. that the t value is significant at 0.1 level.
Answer: B
Explanation:
Pooled estimate of variance needs to be computed as follows:
2 2 2
S = [(60 - 1)(5.876) + (60 - 1)(4.986) ] / (60 + 60 - 2) = 29.694.
1/2
Now determine the value of t. t = [(0.7 - 1.8) - 0] / [29.964/60 + 29.964/60] = -1.101. We reject null if t >
1 .658 or t -1.658 (t-value: t(118, 0.05) = 1.658). The t value of -1.101 does not fit the rejection criteria. In other words we do not reject the null hypothesis and the t value is not significant at the 0.1 level.

NEW QUESTION: 4
ホットスポットの質問
Subscription1という名前のAzureサブスクリプションがあります。
Subscription1で、WebApp1という名前のAzure Webアプリを作成します。 WebApp1は、証明書認証を必要とする外部サービスにアクセスします。
WebApp1にアクセスするにはHTTPSの使用を要求する予定です。
WebApp1に証明書をアップロードする必要があります。
どの形式で証明書をアップロードする必要がありますか?回答するには、回答エリアで適切なオプションを選択します。
注:それぞれの正しい選択には1ポイントの価値があります。

Answer:
Explanation:

Explanation:
A PFX file contains the public key file (SSL Certificate) and its unique private key file. This is required for HTTPS access. The web app will distribute the public key (in a CER file) to clients that connect to the web app.
The CER file is an SSL Certificate which has the public key of the external service. The external service will have the private key associated with the public key contained in the CER file.

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